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  4. If the frequency of the incident light is doubled, the kinetic energy of the emmitted electron will be

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Q. If the frequency of the incident light is doubled, the kinetic energy of the emmitted electron will be

AMUAMU 2000

Solution:

From Planck's law, energy of emitted electrons is
$E=h v$
where $h$ is Planck's constant, $v$ the frequency.
$\therefore $ Given, $v_{2}=2 v_{1}$
$\therefore \frac{E_{2}}{E_{1}}=\frac{v_{2}}{v_{1}}$
$\Rightarrow E_{2} =\frac{2 v_{1}}{r_{1}} E_{1}$
$=2 E_{1}$
Hence, energy of emitted electrons is also doubled.