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  4. If the frequency of incident light falling on a photosensitive metal is doubled, the kinetic energy of the emitted photoelectron is

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Q. If the frequency of incident light falling on a photosensitive metal is doubled, the kinetic energy of the emitted photoelectron is

KEAMKEAM 2014Dual Nature of Radiation and Matter

Solution:

By Einstein's photoelectric equation, The kinetic energy of photoelectrons
$KE =h v -\phi$
where $v=$ frequency of incidence light
and $KE ^{'}=2\, h v-\phi$
So, the kinetic energy is more than twice its initial value.