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Q. If the formula of basic Beryllium nitrate is $\left[B e_{n} O \left(N O_{3}\right)_{6}\right]$ . What is the value of 'n' here

NTA AbhyasNTA Abhyas 2020The s-Block Elements

Solution:

Basic Beryllium nitrate is $\left[B e_{4} O \left(N O_{3}\right)_{6}\right]$

$2 \text{n} - 2 - 6 = 0$

Hence, $n=4$