Question

If the equilibrium constant for the given reaction is $0.25$
$NO \rightleftharpoons \frac{1}{2}N_{2} +\frac{1}{2}O_{2}$, then the equilibrium constant for the reaction $\frac{1}{2}N_{2} +\frac{1}{2}O_{2}\rightleftharpoons NO$ will be

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (D)

$NO \rightleftharpoons \frac{1}{2}N_{2} +\frac{1}{2}O_{2}$ ; $K_{c}=0.25$
$\frac{1}{2}N_{2} +\frac{1}{2}O_{2}\rightleftharpoons NO$ ;
$K_c = \frac{1}{0.25}=4$