Question

If the equilibrium constant for $A \rightleftharpoons B + C$ is $K _{ eq }^{( 1)}$ and that of $B + C \rightleftharpoons P$ is $K _{ eq }^{(2)},$ the equilibrium constant for $A \rightleftharpoons P$ is :-

• A. $K _{ eq }^{(2)}- K _{ eq }^{( 1)}$
• B. $K _{ eq }^{(1)} K _{ eq }^{(2)}$
• C. $K _{ eq }^{( 1 )} / K _{ eq }^{(2)}$
• D. $K_{e q}^{(1)}+K_{e q}^{(2)}$

Answer 1

Answer: (B)

$A \rightleftharpoons B + C$ $K _{ eq }^{( 1 )}=\frac{[ B ][ C ]}{[ A ]}\,\,\,\,\, ....(1)$

$B + C \rightleftharpoons P _{ eq }^{(2)}=\frac{[ P ]}{[ B ][ C ]}\,\,\,\,\, ...(2)$

For

$A \rightleftharpoons P K _{ eq }=\frac{[ P ]}{[ A ]}$

Multiplying equation $ (1)$ & $(2)$

$K _{ eq }^{(1)} \times K _{ eq }^{(2)}=\frac{[ P ]}{[ A ]}= K _{ eq }$