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Q. If the enthalpy of vaporization of water is $186.5 \, kJ \, mol^{-1} $, the entropy if its vaporization will be :

Thermodynamics

Solution:

Given enthalpy of vapourization
$\Delta H = 186.5 \, kJ \, mol^{-1}$
Boiling point of water
$ = 100^{\circ} C = 100 + 273 = 373 K$
$\Delta S = \frac{\Delta H}{T} = \frac{186.5 \, kJ \, mol^{-1}}{373 K}$
$ = 0.5 \, kJ \, mol^{-1} k^{-1}$