1. Tardigrade
  2. Question
  3. Chemistry
  4. If the enthalpy and entropy change for the reaction A 2( g )+ B 2( g ) leftharpoons 2 AB ( g ) are 75 kJ mol -1 and 250 JK -1 mol -1 respectively. The temperature at which the reaction will be at equilibrium is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the enthalpy and entropy change for the reaction
$A _{2}( g )+ B _{2}( g ) \rightleftharpoons 2 AB ( g )$ are $75\, kJ\, mol ^{-1}$
and $250\, JK ^{-1}\, mol ^{-1}$ respectively. The temperature at which the reaction will be at equilibrium is

Solution:

$\Delta G=\Delta H-T \Delta S$
$\therefore $ At equilibrium, $\Delta G=0$
$\therefore \Delta H=T \Delta S $
$T=\frac{\Delta H}{\Delta S}=\frac{75000}{250}$
$=300\, K$