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Q.
If the electronegativity difference between two atoms $A$ and $B$ is $2.0$, then the percentage of co-valent character in the molecule is
Uttarkhand PMTUttarkhand PMT 2008
Solution:
According to Hannay and Smith equation
$\therefore \%$ ionic character $=16\left(x_{A}-x_{B}\right)+3.5\left(x_{A}-x_{B}\right)^{2}$
where, $x_{A}$ and $x_{B}$ are the electronegativites of the atoms $A$ and $B$ respectively.
$\therefore \%$ ionic character $=16(2)+3.5(2) 2$
$=32+14=46$