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  4. If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

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Q. If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

VITEEEVITEEE 2014Atoms

Solution:

As we know $\frac{1}{\lambda}= R \left(\frac{1}{2^{2}} - \frac{1}{3^{2}} \right)$
$= R \left(\frac{1}{4} - \frac{1}{9}\right)$
$ \frac{1}{\lambda} = R \left(\frac{9-4}{36}\right) = \frac{5R}{36}$
$ \therefore \lambda = \frac{36}{5R }$