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Q. If the electric current in a lamp decreases by $5 \%,$ then the power output decreases by

Gujarat CETGujarat CET 2006Electromagnetic Induction

Solution:

Power of lamp
$ P=i^2R $
or $ \frac {dP}{P}=2 \frac {\Delta i}{i}= 2 \times 5 \% \bigg (\because \frac {\Delta i}{i}=5 \% \bigg ) $
$ =10 \% \$ decrease