Thank you for reporting, we will resolve it shortly
Q.
If the density of hydrogen gas at NTP is $0.0000893\, g / cm ^{3}$, then the root mean square velocity of molecules of hydrogen molecules at NTP is:
J & K CETJ & K CET 2001
Solution:
The root mean square velocity $\left(v_{r m s}\right)$ is by
$v_{r m s}=\sqrt{\frac{3 P}{\rho}}$
where $P$ is pressure and $p$ the density.
Given, $P=1.013 \times 10^{3} $ At.
$ \rho=0.0000893\, g / cm ^{3} $
$\rho=0.0000893 \times 1000\, kg / m ^{3} $
$\therefore v_{r m s}=\sqrt{\frac{3 \times 1.013 \times 10^{5}}{0.0000893 \times 1000}} $
$v_{r m s} \approx 1840\, m / s$