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Q. If the de-Broglie wavelength of a particle of mass $m$ is $100$ times its velocity then its value in terms of its mass $ (m) $ and Plants constant $ (h) $ is

J & K CETJ & K CET 2009Structure of Atom

Solution:

Let the velocity of the particle $ =v $
$ \therefore $ Wavelength $ (\lambda ) $ of the particle
$ =100\,v $ or $ v=\frac{\lambda }{100} $
de-Broglie relationship is $ \lambda =\frac{h}{m.v} $
$ \lambda =\frac{h\times 100}{m.\lambda } $
or $ {{\lambda }^{2}}=\frac{h\times 100}{m} $
$ \lambda =10\sqrt{\frac{h}{m}} $