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Q. If the charge on an object is doubled then electric field becomes

Electric Charges and Fields

Solution:

As $E=\frac{1}{4\pi\varepsilon_{0}} \frac{q}{r^{2}}$
If $q'=2q$, then $E'=\frac{1}{4\pi\varepsilon_{0}} \frac{2q}{r^{2}}$ or $E'=2E$
So electric field is doubled.