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Physics
If the charge on a capacitor is increased by 2 coulomb, the energy stored in it increases by 21 %. The original charge on the capacitor is
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Q. If the charge on a capacitor is increased by $2$ coulomb, the energy stored in it increases by $21\%$. The original charge on the capacitor is
WBJEE
WBJEE 2009
A
10 C
B
20 C
C
30 C
D
40 C
Solution:
According to question
$\frac{\frac{q_{f}^{2}}{2 C}-\frac{q_{i}^{2}}{2 C}}{\frac{q_{i}^{2}}{2 C}} \times 100=21$
and $q_{f}-q_{i}=2$
Solving, we get $q_{i}=20 \,C$.