1. Tardigrade
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  3. Chemistry
  4. If the CFSE of [ Ti ( H 2 O )6]3+ is -96.0 kJ / mol, this complex will absorb maximum at wavelength nm. (nearest integer) Assume Planck's constant ( h )=6.4 × 10-34 Js, Speed of light ( c )=3.0 × 108 m / s and Avogadro's Constant ( N A )=6 × 1023 / mol.

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Q. If the CFSE of $\left[ Ti \left( H _2 O \right)_6\right]^{3+}$ is $-96.0\, kJ / mol$, this complex will absorb maximum at wavelength ___$nm$. (nearest integer)
Assume Planck's constant $( h )=6.4 \times 10^{-34} \,Js$, Speed of light $( c )=3.0 \times 10^8\, m / s$ and Avogadro's Constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$.

JEE MainJEE Main 2023Coordination Compounds

Solution:

$ \left( Ti ^{+3}\left( H _2 O \right)_6\right)^{3+} $
$ Ti ^{+3}: 3 d ^1$
$ \text { C.F.S.E. }=-0.4 \times \Delta_0$
$ =-\frac{96 \times 10^3}{ N _0} J $
$\Delta_0 =\frac{96 \times 10^3}{0.4 \times 6 \times 10^{23}} $
$ \Rightarrow \frac{ hc }{\lambda} =\frac{96 \times 10^3}{0.4 \times 6 \times 10^{23}} $
$ \lambda =\frac{0.4 \times 6 \times 10^{23} \times 6.4 \times 10^{-34} \times 3 \times 10^8}{96 \times 10^3} $
$ =0.48 \times 10^{-6} m $
$ =480 \times 10^{-9} m $
$ =480 \,nm$