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  4. If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li++ is

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Q. If the binding energy of the electron in a hydrogen atom is $13.6\, eV$, the energy required to remove the electron from the first excited state of $Li^{++}$ is

AIEEEAIEEE 2003

Solution:

The energy of the first excited state of $Li^{++}$ is
$E_{2}=\frac{Z^{2}E_{0}}{n^{2}}=\frac{3^{2}\times13.6}{2^{2}}=30.6\,eV.$