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Q.
If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li2+ is
MGIMS WardhaMGIMS Wardha 2010
Solution:
$ E=-{{Z}^{2}}\frac{13.6}{{{n}^{2}}}eV $ For first excited state $ {{E}_{2}}=-{{3}^{2}}\times \frac{13.6}{4} $ $ =-30.6eV $ Ionization energy for first excited state of $ L{{i}^{2+}} $ is 30.6 eV.