Question

If the binding energy of $N ^{14}$ is $7.5\, MeV$ per nucleons and that of $N ^{15}$ is $7.7\, MeV$ per nucleon, then the energy is required to remove a neutron from $N ^{15}$ is

• A. 5.25 MeV
• B. 0.2 MeV
• C. 10.5 MeV
• D. 0.4 MeV

Answer 1

Answer: (C)

Given, binding energy per nucleon of
$N^{14} = 7. 5\, MeV/$nucleon
Binding energy per nucleon of
$N^{15} = 7 .\, MeV/$nucleon
$\therefore $ Total $BE$ of $N ^{14}=7.5 \times 14 \,MeV$
Total $BE$ of $N ^{15}=7.7 \times 15\,MeV$
Then, the energy required to remove a neutron from $N ^{15}$,
$= BE _{\text {total }} N^{15}- BE _{\text {total }} N ^{14} $
$=(7.7 \times 15-7.5 \times 14) \,MeV =10.5\, MeV$