Thank you for reporting, we will resolve it shortly
Q.
If the area of the triangle formed by the positive X-axis, the normal and the tangent to the circle $(x-2)^{2}+(y-3)^{2}=25$ at the point (5,7) is $A$ then $24 A$ is equal to________.
Equation of normal $4 x-3 y+1=0$
and equation of tangents $3 x+4 y-43=0$
Area of triangle
$=\frac{1}{2}\left(\frac{43}{3}+\frac{1}{4}\right) \times(7)$
$=\frac{1}{2}\left(\frac{172+3}{12}\right) \times 7$
$A =\frac{1225}{24}$
$24 A =1225$
* as positive $x$ -axis is given in the question so question should be bonus.
