Question

If the abcissiae and ordinates of two points P and Q are the roots of equations $x^2 + 2ax - b^2$ = 0 and $y^2 + 2py - q^2$ = 0 respectively, then the equation of the circle with PQ as diameter is

• A. $x^2 + y^2 + 2ax + 2py - b^2 - q^2 = 0$
• B. $x^2 + y^2 - 2ax - 2py + b^2 + q^2 = 0$
• C. $x^2 + y^2 - 2ax - 2py - b^2 - q^2 = 0$
• D. $x^2 + y^2 + 2ax + 2py + b^2 + q^2 = 0$

Answer 1

Answer: (A)

Correct answer is (a) $x^2 + y^2 + 2ax + 2py - b^2 - q^2 = 0$