Given, $ {{T}_{9}}=0 $ and $ \frac{{{T}_{29}}}{{{T}_{19}}}=? $ Let the first term and common difference of an AP is a, d respectively.
Then, $ a+8d=0 $ ...(i) $ \frac{{{T}_{29}}}{{{T}_{19}}}=\frac{a+28d}{a+18d} $
$=\frac{-8d+28d}{-8d+18d}=\frac{20d}{10d}=\frac{2}{1} $
$ \Rightarrow $ $ {{T}_{29}}:{{T}_{19}}=2:1 $