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  4. If the 5 text th order maxima of wavelength 400 nm in YDSE coincides with n text th order maxima of the wavelength 5000 mathringA, then the value of n is

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Q. If the $5^{\text {th }}$ order maxima of wavelength $400 \,nm$ in YDSE coincides with $n^{\text {th }}$ order maxima of the wavelength $5000 \,\mathring{A}$, then the value of $n$ is

Solution:

$\frac{5 \lambda_{1} D}{d}=\frac{n \lambda_{2} D}{d}$
$5 \times 4000=n \times 5000$
$n=4$