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Q. If the $10^{th}$ term of an A.P. is $\frac{1}{20}$ and its $20^{th}$ term is $\frac{1}{10}$, then the sum of its first $200$ terms is :

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Solution:

$T_{10} = \frac{1}{20} = a + 9d \quad...\left(i\right)$
$T_{20} = \frac{1}{10} = a + 19d \quad ...\left(ii\right)$
$a = \frac{1}{200} = d$
Hence, $S_{200} = \frac{200}{2}\left[\frac{2}{200}+\frac{199}{200}\right] = \frac{201}{2}$