Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If tan θ and cot θ are roots of x2+2 a x+b=0, then least value of |a| is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. If $\tan \theta$ and $\cot \theta$ are roots of $x^2+2 a x+b=0$, then least value of $|a|$ is
Complex Numbers and Quadratic Equations
A
$\frac{1}{2}$
B
1
C
2
D
cannot be found.
Solution:
$\tan \theta+\cot \theta=2 a$ and $\tan \theta \cot \theta=b$
Now, $2 a=\tan \theta+\cot \theta \geq 2$ if $\tan \theta>0$
and $2 a=\tan \theta+\cot \theta \leq-2$ if $\tan \theta<0$.
$\Rightarrow 2|a| \geq 2 \Rightarrow|a| \geq 1$
Thus, least value of $|a|$ is 1 .