1. Tardigrade
  2. Question
  3. Mathematics
  4. If tan 25°=x, then ( tan 155°- tan 115°/1+ tan 155° tan 115°) is equal to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $\tan 25^{\circ}=x$, then $\frac{\tan 155^{\circ}-\tan 115^{\circ}}{1+\tan 155^{\circ} \tan 115^{\circ}}$ is equal to

Trigonometric Functions

Solution:

$\frac{\tan \left(180^{\circ}-25^{\circ}\right)-\tan \left(90^{\circ}+25^{\circ}\right)}{1+\left(\tan \left(180^{\circ}-25^{\circ}\right) \tan \left(90^{\circ}+25^{\circ}\right)\right.}=\frac{-\tan 25^{\circ}+\frac{1}{\tan 25^{\circ}}}{2}=\frac{1-x^2}{2 x}$