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  4. If tan-1 y - y + x = 0, then (d2y/dx2)is equal to

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Q. If $tan^{-1} y - y + x = 0, then \frac{d^2y}{dx^2}$is equal to

Solution:

Correct answer is (a) $\frac{-2(1+y^2)}{y^5}$