Thank you for reporting, we will resolve it shortly
Q.
If $t$ is the parameter for one end of a focal chord of the parabola $y^2 = 4ax$, then its length is
Conic Sections
Solution:
If $t, t'$ are the ends of the focal chord of parabola $y^{2}= 4ax$, then its length $ = a\left(t'-t\right)^{2}$
But for a focal chord $tt' =-1$
$ \therefore t' = -\frac{1}{t}$
$\therefore $ reqd. length $= a\left(-\frac{1}{t} -t\right)^{2}$
$= a\left(t+\frac{1}{t}\right)^{2}$