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  4. If σ = surface charge density, ε = electric permittivity, the dimensions of (σ /ε ) are same as:

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Q. If $ \sigma = $ surface charge density, $ \varepsilon = $ electric permittivity, the dimensions of $ \frac{\sigma }{\varepsilon } $ are same as:

ManipalManipal 2005Electric Charges and Fields

Solution:

The electric field due to conducting infinite sheet is
$ E=\frac{\sigma }{\varepsilon } $