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  4. If σ= surface charge density, ε= electric permittivity the dimensions of (σ/ε) are same as

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Q. If $\sigma=$ surface charge density, $\varepsilon=$ electric permittivity the dimensions of $\frac{\sigma}{\varepsilon}$ are same as

AMUAMU 2006

Solution:

The electric field due to conducting infinite sheet is $E=\frac{\sigma }{\varepsilon } $