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Q. If $\sec ^{2} \theta=\frac{4}{3}$, then the general value of $\theta$ is

Trigonometric Functions

Solution:

We have $\sec ^{2} \theta=\frac{4}{3} $
$\Rightarrow \cos ^{2} \theta=\frac{3}{4}$
$\Rightarrow \cos ^{2} \theta=\cos ^{2}\left(\frac{\pi}{6}\right)$
$\Rightarrow \theta= n \pi \pm \frac{\pi}{6} \ldots \ldots \ldots$