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Q. If $S+O_{2} \rightarrow SO_{2};ΔH=-298.2kJmol^{- 1}$
$SO_{2}+1/2O_{2} \rightarrow SO_{3};ΔH=-98.7kJmol^{- 1}$
$SO_{3}+H_{2}O \rightarrow H_{2}SO_{4};ΔH=-130.2kJmol^{- 1}$
$H_{2}+1/2O_{2} \rightarrow H_{2}O;ΔH=-287.3kJmol^{- 1}$
Then the enthalpy of formation of $H_{2}SO_{4}$ at $298K$ is-

NTA AbhyasNTA Abhyas 2020

Solution:

$ΔH=ΔH_{1}+ΔH_{2}+ΔH_{3}+ΔH_{4}$