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Mathematics
If S1 and S2 are respectively the sets of local minimum and local maximum points of the function, f(x) = 9x4 + 12x3 - 36x2 + 25, x ∈ R, then :
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Q. If $S_1$ and $S_2$ are respectively the sets of local minimum and local maximum points of the function, $f(x) = 9x^4 + 12x^3 - 36x^2 + 25, x \in R$, then :
JEE Main
JEE Main 2019
Application of Derivatives
A
$S_1 = \{ -2, 1\} ; S_2 = \{0 \}$
58%
B
$S_1 = \{ -2, 0\} ; S_2 = \{1 \}$
21%
C
$S_1 = \{ -2\} ; S_2 = \{0 , 1 \}$
21%
D
$S_1 = \{ -1\} ; S_2 = \{0 , 2 \}$
0%
Solution:
$f\left(x\right) =9x^{4} +12x^{3} -36x^{2} +25 $
$ f'\left(x\right) =36x^{3} + 36x^{2} -72x $
$ =36x\left(x^{2}+x-2\right) $
$ =36x\left(x-1\right)\left(x+2\right) $
Points of minima = {-2, 1} = $S_1$
Point of maxima = {0} = $S_2$