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  4. If rotational kinetic energy is 50 % of total kinetic energy then the body will be:-

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Q. If rotational kinetic energy is $50 \%$ of total kinetic energy then the body will be:-

System of Particles and Rotational Motion

Solution:

Given, $\frac{K_{\text {Rotation }}}{K_{\text {Total }}} 100=50 \%$
$\Rightarrow \frac{\frac{K^{2}}{R^{2}}}{1+\frac{K^{2}}{R^{2}}} \times 100=50$
$\Rightarrow \frac{\frac{K^{2}}{R^{2}}}{1+\frac{K^{2}}{R^{2}}}=\frac{1}{2}$
so, $\frac{K^{2}}{R^{2}}=1,$ so it is a ring