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Q. If resonant frequency of a $R-L-C$ circuit is $\omega_{0}$ and bandwidth is $A \omega$, then which of the following quantity is regarded as a measure of the sharpness of resonance?

Alternating Current

Solution:

The quantity $\left(\omega_{0} / 2 \Delta \omega\right)$ is regarded as measure of the sharpness of resonance. The smaller the $\Delta \omega$, the sharper is the resonance.