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Physics
If resistivity of copper is 1.72 × 10-8 Ω-m and number of free electrons in copper is 8.5 × 1028 / m 3. Find mobility.
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Q. If resistivity of copper is $1.72 \times 10^{-8} \Omega$-m and number of free electrons in copper is $8.5 \times 10^{28} / m ^{3}$. Find mobility.
JIPMER
JIPMER 2019
Semiconductor Electronics: Materials Devices and Simple Circuits
A
$4.25 \times 10^{-3} m ^{2} / C \Omega$
50%
B
$6.8 \times 10^{-3} m ^{2} / C \Omega$
23%
C
$8.5 \times 10^{-3} m ^{2} / C \Omega$
11%
D
$3.4 \times 10^{-3} m ^{2} / C \Omega$
16%
Solution:
Given,
Resistivity of Copper = 1.72 $\times$ 10
-8
$\Omega$-m
Number of free electrons, n = 8.5 $\times$ 10
28
/m3
Mobility, $\mu = \frac{1}{\rho ne}$
$=\frac{1}{1.72\times10^{-8}\Omega m\times8.5\times10^{28}/m^{3}\times1.6\times10^{-19}}$
$=4.25\times10^{-3}m^{2}/C\Omega$