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Q. If radius of first orbit of hydrogen atom is $5.29 \times 10^{-11} \,m$, the radius of fourth orbit will be

Atoms

Solution:

$5.3 \times 10^{-11}$
or $0.53 \,\mathring{A}$
Radius of $n^{\text {th }}$ orbit $=0.53 \times n^{2}$
Radius of $4^{\text {th }}$ orbit $=0.53 \times 16\,\mathring{A}$
$=8.46 \,\mathring{A}$