1. Tardigrade
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  3. Chemistry
  4. If r+ / r- lies between 0.414 to 0.732, the cation will occupy

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Q. If $r_{+} / r_{-}$ lies between 0.414 to $0.732,$ the cation will occupy

The Solid State

Solution:

Radius ratio $=\frac{\text { radius of the cation }\left(r_{+}\right)}{\text {radius of the anion }\left(r_{-}\right)}$

If radius ratio lies in the range of $0.414-0.732,$ its coordination number will be 6 and the cation will occupy the octahedral void.