Let the length of sides are $a, b$ and $c$, so $s=\frac{a +b +c}{2}$
Now, from the diagram area of triangle $A B C$ is
$\Delta =\Delta I B C+\Delta I C A+\Delta I A B$
$=\frac{1}{2} a r+\frac{1}{2} b r+\frac{1}{2} c r$
$\Delta =r\left(\frac{a+b+c}{2}\right)=r s$