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Q. If $q=q_{0}(1-e^{\frac{-\tau}{RC}}]$ Here, $q =$ electric charge, $R =$ electric resistance, $C =$ electric capacitance. The dimensional formula for ${\tau}$ are

Physical World, Units and Measurements

Solution:

$\left[RC\right]$ is time constant $=\left[M^{0}L^{0}T\right]$
Exponents have no dimensions
$\therefore \frac{\tau}{RC}=\left[M^{0}L^{0}T\right]$
$\Rightarrow \tau=\left[M^{0}L^{0}T\right]$