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Chemistry
If pressure increases by 1 % then percentage decrease of volume of an ideal gas at constant temperature is
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Q. If pressure increases by $1\%$ then percentage decrease of volume of an ideal gas at constant temperature is
NTA Abhyas
NTA Abhyas 2020
A
$\frac{100}{101}\%$
B
$1.11\%$
C
$\frac{101}{100}\%$
D
$10.1\%$
Solution:
$P_{1}V_{1}=P_{2}V_{2}$
$100\times V_{1}=101\times V_{2}\Rightarrow V_{2}=\frac{100}{101}V_{1}$
$\%$ decrease in volume $=\frac{V_{1} - V_{2}}{V_{1}}\times 100$
$=\left(1 - \frac{100}{101}\right)\times 100$
$=\frac{100}{101}\%$