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  4. If potential energy of an electron in a hydrogen atom in first excited state is taken to be zero, kinetic energy (in eV) of an electron in ground state will be

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Q. If potential energy of an electron in a hydrogen atom in first excited state is taken to be zero, kinetic energy (in eV) of an electron in ground state will be

Atoms

Solution:

If zero of potential energy is changed,
$KE$ does not change and continues to be $+13.6 \,,eV$.
When $2^{\text {nd }}$ shell is taken as reference,
ground state $PE$
$=-13.6\, eV \times 2+6.8\, eV$
$ =-20.4\, eV$
$KE =\frac{- PE }{2}$
$=10.2\, eV$