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  4. If potassium chlorate is 80 % pure, then 48 g of oxygen would be produced from (atomic mass of K= 39) ;

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Q. If potassium chlorate is $80\%$ pure, then $48 \,g$ of oxygen would be produced from (atomic mass of $K= 39$) ;

Some Basic Concepts of Chemistry

Solution:

$\underset{2 \times 122.5 g}{2 KClO _3 }\rightarrow 2 KCl + \underset{3 times g}{3 O _3}$
$3 \times 32 g$ of $O _2 2$ is produced from $KClO _3=245 g$
$48 g$ of $O _2$ is produced from $KClO _3=122.5 g$
$\therefore 80 \% KClO _3$ needed $=\frac{122.5 g \times 100}{80}$
$=153.12 g$