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Q. If pH value of a solution is $3$ and by adding water, it becomes $6$, then the dilution is increased by

AIIMSAIIMS 1995Equilibrium

Solution:

Given: Initial $pH =3$ and final $pH =6 . We$ know that $pH \propto$ Dilution.

Therefore initially $\left[ H ^{+}\right]=$ $10^{-3}$ and after dilution $\left[ H ^{+}\right]=10^{-6} $ Thus increase in dilution

$=\frac{\text { Original } H ^{+} \text {concentration }}{\text { Concentration of } H +\text { after dilution }}=\frac{10^{-3}}{10^{-6}}=10^{3} $

$=1000$ times