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  4. If Pauli exclusion principle allows three electron an orbital, and other rules are remaining same then find the block of Co(.Z=27.)

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Q. If Pauli exclusion principle allows three electron an orbital, and other rules are remaining same then find the block of $Co\left(\right.Z=27\left.\right)$

NTA AbhyasNTA Abhyas 2022

Solution:

$Co\left(\right.27\left.\right):-1s^{3},2s^{3},2p^{9},3s^{3},3p^{9}$ (If one orbital allows three electrons)