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Q.
If path difference becomes $ (2n-1)\frac{\lambda }{2} $ then:
Jharkhand CECEJharkhand CECE 2006
Solution:
Path difference is odd multiple of $ \frac{\lambda }{2}. $
Given path difference $ =(2n-1)\frac{\lambda }{2} $
which is an odd multiple of
$ \frac{\lambda }{2}. $
Hence, destructive interference takes place and dark fringe is formed.