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  4. If (p ∧ ∼ r) ⇒ (q ∨ r) is false and q and r are both false, then p is

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Q. If $\left(p\, \wedge \sim r\right) \Rightarrow \left(q \vee r\right)$ is false and $q$ and $r$ are both false, then $p$ is

Mathematical Reasoning

Solution:

Given result means $p\, \wedge \sim r$ is true, $q \vee r$ is false.