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  4. If p, q, r are simple propositions with truth values T, F, T, then the truth value of (∼ p ∨ q) ∧ ∼ r ⇒ p is

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Q. If p, q, r are simple propositions with truth values T, F, T, then the truth value of $\left(\sim p \vee q\right) \wedge \sim r \Rightarrow p $ is

VITEEEVITEEE 2015

Solution:

$\sim p \vee q$ means $F \vee F = F, \sim r$ means $F$
$\therefore \left[\left(\sim p \vee q\right) \wedge \sim r\right] \Rightarrow p$ means $T$