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Q. If $P, P'$ represent the complex number $z_1$ and its additive inverse respectively, then the complex equation of the circle with $PP'$ as a diameter is

Complex Numbers and Quadratic Equations

Solution:

Clearly $\left|z\right|=\left|z_{1}\right|$
$\Rightarrow \left|z\right|^{2}=\left|z_{1}\right|^{2}$

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$\Rightarrow z\,\bar{z}=z_{1}\,\bar{z}_{1}$
$\Rightarrow \frac{z}{z_{1}}=\frac{\overline{z}_{1}}{\bar{z}}=\left(\frac{\overline{z}}{z}\right)$