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  4. If P(F)=(1/2), P(G)=(4/5), P(E ∩ F ∩ G)=(3/10) and P(EC ∩ F ∩ G)=(1/10). The value of P(F / G) is

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Q. If $P(F)=\frac{1}{2}, P(G)=\frac{4}{5}, P(E \cap F \cap G)=\frac{3}{10}$ and $P\left(E^C \cap F \cap G\right)=\frac{1}{10}$. The value of $P(F / G)$ is

Probability - Part 2

Solution:

$P(F / G)=\frac{P(F \cap G)}{P(G)}=\frac{4}{10} \cdot \frac{5}{4}=\frac{1}{2}$

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