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Q. If $P ( A \cap B )=0.15, P \left( B ' \right)=0.10$, then $P ( A / B )=$

Probability - Part 2

Solution:

$P ( A / B )=\frac{ P ( A \cap B )}{ P ( B )}$
$=\frac{0.15}{1- P \left( B '\right)}$
$=\frac{0.15}{1-0.1}$
$=\frac{15}{90}$
$=\frac{1}{6}$